Solved example of BODMAS
QUESTION: `d=frac{3a²+2b}{4(c+3)}` where
a =
-2
b = 2
and
c =
-4
Work
out the value of `d`.
SOLUTION:
BODMAS rule is used to remember the order of operations
to be followed while solving expressions in mathematics.
Here `d=frac{3a^2+2b}{4(c+3)}` ——–(Equation
1)
STEP 1: Put
a =
-2,
b = 2
and
c =
-4
in
(Equation 1)
`d=frac{3(-2)^2+2times2}{4(-4+3)}`
Now
apply BODMAS rule
STEP 2: Work out Brackets first
`d=frac{3(-2)^2+2times2}{4(-1)}`
putting
brackets round negative number makes it clear that -1 is multiplied by 4, not 1
subtracted from 4
STEP 3: The other stuff- in this case square
`d=frac{3times4+2times2}{4(-1)}`
STEP 4: There is no division in numerator and denominator in
this case, so do multiplication
`d=frac{12+4}{-4}`
STEP 5: Then addition
`d=frac{16}{-4}`
Numerator
and denominator are simplified.
STEP 6: Now work out division.
`d=-4`
Its really important to check your working on BODMAS questions. You might be certain you did it right, but its surprisingly easy to make a slip.
Try out this practice question and share its answer in comment below. Let me see how you do.
`d=(a-7)^2+frac{4b}{c+1}` where
`a=4`
`b=3`
`c=-2`
Work out the value of `d`